-5x^2+58=0

Solution for -5x^2+58=0 equation:

-5x^2+58=0

a = -5; b = 0; c = +58;
Δ = b2-4ac
Δ = 02-4·(-5)·58
Δ = 1160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1160}=\sqrt{4*290}=\sqrt{4}*\sqrt{290}=2\sqrt{290}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{290}}{2*-5}=\frac{0-2\sqrt{290}}{-10}
=-\frac{2\sqrt{290}}{-10}
=-\frac{\sqrt{290}}{-5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{290}}{2*-5}=\frac{0+2\sqrt{290}}{-10}
=\frac{2\sqrt{290}}{-10}
=\frac{\sqrt{290}}{-5}
$